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x^2=5x+36x^2=5x+36
We move all terms to the left:
x^2-(5x+36x^2)=0
We get rid of parentheses
x^2-36x^2-5x=0
We add all the numbers together, and all the variables
-35x^2-5x=0
a = -35; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·(-35)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*-35}=\frac{0}{-70} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*-35}=\frac{10}{-70} =-1/7 $
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